Question

X=acos cube theta, y=bsin cube theta
Prove that (x/a)2/3+(y/b) 2/3=1

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

[question]: If x=acos^3A, y=bsin^3A, Prove that [x/a]^2/3+[y/b^2/3=1.

~  x=acos^3A

   x/a=cos^3A

    y=bsin^3A

    y/b=sin^3A

LHS=

=[x/a]^2/3 + [y/b]^2/3

=[cos^3A]2/3 + [sin^3A]2/3

=cos²A + sin²A

=1  =RHS