x and y are two digit natural numbers such that digits are a & b and c & d respectively with a+b+c+d=18. If y=3x and (y-x) is a perfect square find possible values of x and y
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x and y are two digit natural numbers such that digits are a & b and c & d respectively with a+b+c+d=18. If y=3x and (y-x) is a perfect square possible values of x and y are x= 18 and y=54
uddipta29:
I will be glad, if u provide me with the steps
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