Question

X and Y are two sets such that Xhas 21 elements. Y has 32 elements
and 11 elements are common to X and Y then n(XUY) - ?
- 64
muy (4
)
(4)
none of these​

Answer 1

The value of $n(X\bigcup Y)=42$

Step-by-step explanation:

• Given that X and Y are two sets such that X has 21 elements and Y has 32 elements
• That can be written as n(X)=21 and n(Y)=32
• Also given that 11 elements are common to X and Y
• That is $n(X\bigcap Y)=11$

To find $n(X\bigcup Y)$ :

We know $n(X\bigcup Y)=n(X)+n(Y)-n(X\bigcap Y)$

• Now substitute the values in the above formula we get

• $n(X\bigcup Y)=21+32-11$
• $=53-11$
• $=42$

Therefore $n(X\bigcup Y)=42$

The value of $n(X\bigcup Y)$ is 42

Option none of these is correct.