Question

X and Y can do a piece of work in 10 days and six days respectively they worked together for two days and why leaves the work in how many days X will finish the remaining work​

Answer 1

There are three methods to solve this problem.

Method-1 Fraction Method

A completes the work in 10 days -> In 1 day he completes 1/10 part of job.

B completes the work in 15 days -> In 1 day he completes 1/15 part of job.

Work done by A & B both in 1 day= 1/10 + 1/15

=(10+15)/(10x15) = 25/150 = 1/6

Let both A & B workd for 'x' days.

Work done by them in x day = x/6

Remaining work = 1-x/6 ………(1)

This remaining work is done by A alone in 5 days.

Hence,

Work done by A in 5 days = Remaining work

5/10 = 1-x/6 …. From (1)

x/6 = 1–1/2

x = 6*1/2

x=3

A & B worked for 3 days.