Math, asked by ChayanikaDutta, 8 months ago

x+ay=1, ax-y=3 (solve by substitution method)​

Answers

Answered by sb229829
2

Step-by-step explanation:

x = b & y = -a

Step-by-step explanation:

Given system of equations:

\frac{ax}{b}-\frac{by}{a}=a+b

b

ax

a

by

=a+b ...................... (1)

ax-by=2abax−by=2ab ....................(2)

from equation (2), we get

ax=2ab+byax=2ab+by

x=\frac{2ab+by}{a}x=

a

2ab+by

......... (3)

Put, this value of eqn (3) in eqn(1)

\frac{a\times\frac{2ab+by}{a}}{b}-\frac{by}{a}=a+b

b

a

2ab+by

a

by

=a+b

\frac{2ab+by}{b}-\frac{by}{a}=a+b

b

2ab+by

a

by

=a+b

\frac{a(2ab+by)-b^2y}{ab}=a+b

ab

a(2ab+by)−b

2

y

=a+b

2a^2b-aby+b^2y=ab(a+b)2a

2

b−aby+b

2

y=ab(a+b)

2a^2b+(ab-b^2)y=a^2b+ab^22a

2

b+(ab−b

2

)y=a

2

b+ab

2

(ab-b^2)y=a^2b+ab^2-2a^2b(ab−b

2

)y=a

2

b+ab

2

−2a

2

b

b(a-b)y=ab^2-a^2bb(a−b)y=ab

2

−a

2

b

b(a-b)y=-ab(a-b)b(a−b)y=−ab(a−b)

y=\frac{-ab(a-b)}{b(a-b)}y=

b(a−b)

−ab(a−b)

y=-ay=−a

Now, Put value of y in eqn (3)

x=\frac{2ab-ba}{a}x=

a

2ab−ba

x=\frac{ab}{a}x=

a

ab

x=bx=b

Therefore, x = b & y = -a

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