Question

x= cos 10^°-sin 10^° then the value of x is

Answer 1

Answer:

x>0

Step-by-step explanation:

cos10^°-sin10^°

=cos(90-10)^°-sin10^°. (cos(90-theta)=sintheta)

=sin80°-sin10°

x>0

Answer 2

The value of x is positive or x>0.

Given:

x= cos 10°-sin 10°

To Find:

The value of x.

Solution:

We know that

sin 0°= 0 , sin 45°= 1/√2 , sin 90° = 1  

and

cos 0°= 1 , cos 45°= 1/√2 , cos 90° = 0

We observe that the graphs of sine and cosine intersect at π/4.

When θ lies between 0 and π/4 (or 45°)

cosθ > sinθ

Hence when 0 ≤ θ ≤ π/4,

x = cosθ - sinθ > 0

Now, as 0 ≤ θ=10° ≤ 45°

x= cos 10°- sin 10° > 0

Therefore the value of x is positive or x>0.

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