Question

X forms an oxide X2O3. 0.36g forms 0.56g of X2O3. atomic weight of X​

Answer 1

Answer:

43.2gm

Explanation:

x=0.36gm

x2O3=0.56gm

0.36gm______0.2 gm Oxygen

xgm_________48gm

X=86.4 gm

at.wt=86.4/2=43.2

Answer 2

Given,

X forms an oxide X2O3

0.36g of X forms 0.56g of X2O3

To find,

The atomic mass of X.

Solution,

We can simply solve this numerical problem by using the following process:

Let us assume that the atomic mass of X is x grams.

And, the atomic mass of an oxygen atom is = 16 g

Now,

The total molecular mass of X2O3

= total molar mass of X2O3

= 2(atomic mass of X) + 3(atomic mass of oxygen)

= 2(x grams) + 3(16 grams)

= (2x + 48) grams

Now, according to the question;

2x grams of element X forms (2x + 48) grams of X2O3 compound

=> By using the unitary method, we get;

By using the unitary method, we get;0.36 grams of X forms {(2x + 48)/2x × 0.36} grams, that is, 0.56 grams of X2O3

=> {(2x + 48)/2x × 0.36} = 0.56

=> (2x + 48)/2x = 56/36

=> 36(x + 24) = 56x

=> 56x = 36x + 864

=> 20x = 864

=> x = 43.2 grams

Hence, the atomic mass of X is equal to 43.2 grams.