Math, asked by Hariram5, 11 months ago

X is 1459.55 more than Y and 542.31 less than Z. If X + Y = 1545.55.Find the value of X+Y+Z

Answers

Answered by otito774
10

Answer: 3,590.41

Step-by-step explanation:

X + Y = 1545.55 ------ equation 1

X = Y + 1459.55 ------ equation 2

X = Z - 542.31 --------- equation 3

From equation 1

X + Y = 1545.55

X = 1545.55 - Y -------- equation 4

To find Y:

Substitute equation 4 into equation 2

X = Y + 1459.55

1545.55 - Y = Y + 1459.55

Y + Y = 1545.55 - 1459.55

2Y = 86

Y = 86/2

Y = 43

To find X:

Substitute Y = 43 into equation 2

X = Y + 1459.55

X = 43 + 1459.55

X = 1502.55

To find Z:

Substitute X = 1502.55 into equation 3

X = Z - 542.31

1502.55 = Z - 542.31

Z = 1502.55 + 542.31

Z = 2044.86

X = 1502.55

Y = 43

Z = 2044.86

X + Y + Z = 1502.55 + 43 + 2044.86

= 3,590.41

Answered by shahwaizasghar321
0

Answer:

X is 1459.55 more than Y

X-1459.55=Y

X-Y=1459.55 .... (1)

X is 542.31 less than Z

X+542.31=Z

X-Z= -542.31 .... (2)

X+Y=1545.55 .... (3)

Solving simultaneously (1) and (3)

X-Y=1459.55

X+Y=1545.55

-------------------------

2X+0=3005.10

X =3005.10/2

X =1502.55 ...... (4)

Put the value of 'X' in equation (3)

X+Y=1545.55

Y= 1545.55-X

Y=1545.55-1502.55

Y=43 ....... (5)

Put the value of X in equation (2)

X-Z= -542.31

-Z= -542.31-X

-Z= -542.31-1502.55

-Z= - 2044.86

Z= 2044.86

Putting the values of X Y and Z in (X+Y+Z)

X+Y+Z=1502.55+43+2044.86

X+Y+Z=3590.41

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