Math, asked by Fairyparrot, 11 months ago

X^m+n × x^n+l × x^l+m/(x^m × x^n × n^l ) ^2 ​

Answers

Answered by BABU1303S
2

=x^m+n+n+l+l+m/(x^m+n+l)^2

=x^2m+2n+2l/x^2m+2n+2l

=x^0

=1(ANSWER)

Hope it helps u

Similar questions