x power 4 plus x power 3 minus 7 x square minus x + 6 factorise it
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maine x ki random value rakhke dekhi jissse p (x) zero kae barabar ho gye aur jab un value sae divide kiya toh mujhe factors mile
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x4+x³-7x²-x+6
=x(x³+x²-7x-1)+6
=x[x(x²+x-7)-1]+6
=x[x{x(x+1)-7}-1]+6
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