x square loge *
find its differentiate the following
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Differentiate using the chain rule, which states that ddx[f(g(x))] d d x [ f ( g ( x ) ) ] is f'(g(x))g'(x) f ′ ( g ( x ) ) g ′ ( x ) where f(x)=log(x) f ( x ) = log ( x ) and g(x)=x2 g ( x ) = x 2 .
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