X takes 3 hours more than y to walk 30 km but if x double space he is applied on head of y by one and a half an hour find the speed of walking
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let us consider x = A and y = B
let speed A = x km /h and speed of B = y km/h
time = distance / speed
time taken to cover 30 km by A = 30/x
B = 30/y
given time taken by A = time taken by B + 3
time taken by A - 3 = time taken by B
30/x - 3 = 30/y
30 - 3x /x = 30/y
30y - 3xy = 30x
30y - 30x = 3xy
30x - 30y = - 3xy
10x - 10y = -xy ....... i
when A doubles his speed
time taken by A + 3/2 = time taken by B
30/2x + 3/2 = 30/y
15/x + 3/2 = 30/y
30y + 3xy = 60x
10y + xy = 20x
20x - 10y = xy ....... ii
10x - 10y = -xy from i
10x = 2xy
y = 5
10x - 50 = - 5x
15x = 50
x=50/15 = 10 / 3
Hence speed of A = 10/3 km/h
that of B = 5 km/h
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