Question

x
$x {}^{3} + {13}^{2} + ax + 35$
is one factor x + 5, then find the value of a ?

Answer 1

$\huge\mathbb{SOLUTION:-}$

"Refer the pic for the solution"

$\huge\mathbb{STEPS:-}$

1. First you find the value of x

x+5=0

x=-5

2. Now substitute the value of x in

the given equation

3. you would get a answer in

fraction form 79/5

4. Alternatively, you can write

79/5 as 15.8

Answer 2

$\huge\boxed{\fcolorbox{blue}{bold}{Question}}$

$x {}^{3} + {13}^{2} + ax + 35$
is one factor x + 5, then find the value of a

$\huge\boxed{\fcolorbox{blue}{bold}{Answer}}$

(x-5 is the factor of polynomial so x= -5)

$- 5 {}^{3} + 13 {}^{2} - 5a + 35 = 0 \\ = > - 125 + 169 - 5a + 35 = 0 \\ = > - 125 + 204 - 5a = 0 \\ = > 79 - 5a = 0 \\ = > - 5a = - 79 \\ = > a = - 79 \div - {5} \\ = > a = 79 \div 5$

hope it helps you...