Question

X varies inversely as y3 if x is 16 when Y is 4 find X when Y is to​

Answer 1

Answer:

Answer:

x varies inversely as y^3

So x y^3 is constant

if x=16, y=5

So, xy^3 = 16(5)^3

=16(125)

= 2000

So, Value of x when y=2

= 2000/(2)^3

=2000/8

=250

So, X=250

Answer 2

Answer:

IT varies inversely as y^3

IF X=16,Y=5

SO XY^3=16(5)^3

=> 16(125)

=> 2000

SO VALUE OF X WHEN Y=2

=>2000/(2)^3

=>2000/8

= 250

SO, X =250