Question

) x+y=5 and 2x – 3y=4​

Answer 1

Answer:

${\sf{\therefore x=\frac{19}{5}}}$

${\sf{\therefore y=\frac{6}{5}}}$

Explanation:

$\huge{\underline{\sf{SOLUTION-}}}$

• In the given question information given about two equation in which two variables are known.

• We have to find these two variable.

$\: \: \: \: \bold{Given:}\\\\ \bold{\implies x + y = 5} \\ \\\bold{2x - 3y= 4} \\ \\ \bold{To \: Find}\\ \\ \bold{\implies x = }\\ \\\bold{\implies y = }$

• According to given question:

• Using substitution method to solve:

$\implies x + y = 5 \\\\ \implies x = 5 - y - - - - - (1) \\ \\ \implies 2x - 3y = 4 - - - - - (2) \\\\ \bold{putting \: value \: of \: x \: (2)} \\\\ \implies 2 (5 - y) - 3y = 4 \\ \\\implies 10 - 2y - 3y = 4 \\ \\ \implies -5y = 4 - 10 \\ \\ \implies y = \frac{ - 6}{ - 5} \\ \\ \bold{ \therefore y = \frac{6}{5} } \\ \\ \bold{putting \: value \: of \: y \: in(1)} \\ \\ \implies x = 5 - y \\ \\\implies x = 5 - \frac{6}{5} \\ \\ \implies x = \frac{25 - 6}{5} \\ \\ \bold{ \therefore x = \frac{19}{5} }$

Answer 2

$x + y = 5 \\ > 2x + 2y = 10 - - - - \: i \\ \\ 2x - 3y = 4 - - - - - ii \\ \\ \\ substracing \: ii \: from \: i \\ > 2x + 2y - 2x + 3y = 10 - 4 \\ > 5y = 6 \\ y = \frac{6}{5} \\ \\ \\ putting \: y = \frac{6}{5} in \: i \\ 2x + 2 \times \frac{6}{5} = 10 \\ 2x = 10 - \frac{12}{5} \\ 2x = \frac{50 - 12}{5} \\ 2x = \frac{38}{5} \\ x = \frac{19}{5}$