(x-y) cube+(y-z)cube+(z-x)cube
Solve using identities
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Note that (x - y) + (y - z) + (z - x) = 0
Hence use the fact a^3 + b^3 + c^3 = 3abc if a + b + c = 0 and proceed.
Hence use the fact a^3 + b^3 + c^3 = 3abc if a + b + c = 0 and proceed.
fairyno1:
But can u just tell the answer with explanation because I am not confident solving maths
So o please explain further as well
Yeah, sure.
Suppose a = x - y, b = y - z, c = z - x.
Then a + b + c = 0
Now, we know that a^3 + b^3 + c^3 = 3abc
When a + b + c = 0
Hence, (x-y)^3 + (y-z)^3 + (z-x)^3 = 3(x-y)(y-z)(z-x).
Simplify this and you'll get the answer.
Thanks
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