India Languages, asked by aryanv1455, 10 months ago

x,y ஐ தீர்க்க ((x^2@y^2 ))+ 2((-2x@-y))=((-5@8))

Answers

Answered by Anonymous
1

Answer:

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Answered by steffiaspinno
0

x ன் மதிப்புகள் = -1 , 5

yன் மதிப்புகள் = -2, 4

விளக்கம்:

\left(\begin{array}{l}x^{2} \\y^{2}\end{array}\right)+2\left(\begin{array}{c}-2 x \\-y\end{array}\right)=\left(\begin{array}{c}-5 \\8\end{array}\right)

\left(\begin{array}{l}x^{2} \\y^{2}\end{array}\right)+\left(\begin{array}{c}-4 x \\-2 y\end{array}\right)=\left(\begin{array}{c}-5 \\8\end{array}\right)

x^{2}-4 x=-5

x^{2}-4 x+5=0

(x+1)(x-5)=0

x + 1 = 0

x = -1

x - 5 = 0

x = 5

y^{2}-2 y=8

y^{2}-2 y-8=0

(y-4)(y+2)=0

y - 4 = 0

y = 4

y + 2 = 0

y = -2

x ன் மதிப்புகள் = -1 , 5

yன் மதிப்புகள் = -2, 4

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