Question

X, y, z are three real number and x+y+z=18 find the value of x2y3z4

Answer 1

x+2y+3z+4=18
x+2y+3z = 18-4
x+2y+3z = 14
x+y+z = 14/2*3
x+y+z = 7/3

Answer 2

Answer:

hey mate

here is your answer

7/3

mark me as brainliest