Math, asked by Ajantasahu, 11 months ago

X2+1/X2=8 find X2-1/X2

Answers

Answered by Anonymous
3

 \:\:\:\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \huge\mathcal{\bf{{\underline{\underline{\huge\mathcal{...Answer...}}}}}}

\underline{\large\mathcal\red{solution}}

x {}^{2}   +  \frac{1}{x {}^{2} }  = 8 \\  \: now \:  \:  \:  \\ (x {}^{2}  -  \frac{1}{x {}^{2} } ) {}^{2}  = (x {}^{2}  +  \frac{1}{x {}^{2} }  ){}^{2}- 4( \frac{1}{x {}^{2} } )(x {}^{2} ) \\  =  > (x {}^{2}  -  \frac{1}{x {}^{2} } ) {}^{2}  = 8 {}^{2}  - 4 \\  =  > (x {}^{2}  -  \frac{1}{x {}^{2} })  =  \sqrt{60}  = 2 \sqrt{15}

\large\mathcal\red{hope\: this \: helps \:you......}

Answered by Anonymous
0

\underline{\mathcal\blue{Answer:-}}

\begin{lgathered}x {}^{2} + \frac{1}{x {}^{2} } = 8 \\ \: now \: \: \: \\ (x {}^{2} - \frac{1}{x {}^{2} } ) {}^{2} = (x {}^{2} + \frac{1}{x {}^{2} } ){}^{2}- 4( \frac{1}{x {}^{2} } )(x {}^{2} ) \\ (x {}^{2} - \frac{1}{x {}^{2} } ) {}^{2} = 8 {}^{2} - 4 \\ (x {}^{2} - \frac{1}{x {}^{2} }) = \sqrt{60} = 2 \sqrt{15}\end{lgathered} </p><p>

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