Question

x²-14x + 13 =0 find the valueΔ

Answer 1

${x}^{2} - 14x + 13 = 0$
$= > {x}^{2} - 13x - x + 13 = 0$
$= > (x - 13)(x - 1) = 0$
$so.... \\ x = 13 \\ or... \\ x = 1$