Question

x² + 3√3x + 6
Can you solve this​

Answer 1

${x}^{2} + 3 \sqrt{3} x + 6 \\ \\ {x}^{2} + \sqrt{3} x + 2 \sqrt{3} x + 6 \\ \\ = x(x + \sqrt{3} ) + 2 \sqrt{3} (x + \sqrt{3} ) \\ \\ = (x + 2 \sqrt{3} )(x + \sqrt{3} )$

$x$ = -2√3 and

$x$ = -√3

Answer 2

$\begin{gathered}\sf {x}^{2} + 3 \sqrt{3} x + 6 \\ \\ \sf{x}^{2} + \sqrt{3} x + 2 \sqrt{3} x + 6 \\ \\ \sf= x(x + \sqrt{3} ) + 2 \sqrt{3} (x + \sqrt{3} ) \\ \\\sf = (x + 2 \sqrt{3} )(x + \sqrt{3} )\end{gathered}$

x = -2√3

x = -2√3 x