Question

X²-3x-2=0 completing squares

Answer 1

${x}^{2} - x - 2 = 0 \\ {x}^{2} - x = 2 \\ {x}^{2} - x + { (\frac{1}{2} )}^{2} = 2 + {( \frac{1}{2} )}^{2} \\ {(x + \frac{1}{2}) }^{2} = 2 + \frac{1}{2} \\ {(x + \frac{1}{4}) }^{2} = \frac{8 + 1}{4} \\ x + \frac{1}{2} = \sqrt{ \frac{9}{4} } \\ x + \frac{1}{2} = \frac{3}{2} \\ x = \frac{3}{2} - \frac{1}{2} \\ x = \frac{3 - 1}{2} \\ x = \frac{2}{2} \\ x = 1$
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