Math, asked by pratikshatodsam65, 2 months ago

x2+3y2+2z2=6 at point p(2,0,1) is

Answers

Answered by crazysreekutty

0

Answer:

Step-by-step explanation:

2^2 + 3 ×(0^2) + 2 × (1^2) -6 = 4+0+2-6 = 0

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