(x²+42x+49)²-y².
factorize
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You could take (x square +42x +49)square as "A" and y square as "B"
Then it would fall in the formula A square - B square,which is (A+B)(A-B).
Otherwise you could try splitting the middle term of "A"
Samanwita:
not steps..do that sum
Answered by
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(9x^2 + 42x + 49)^2 - y^2
let 9x^2 + 42x + 49 be 'x'
9x^2 + 42x + 49
(3x)^2 + 2×3x×7 + (7)^2
it's in the form of a^2 +2ab+ b^2 = (a+b)^2
so (3x)^2 + 2×3x×7 + (7)^2 = (3x + 7)^2
so 'x' = (3x + 7)^2
( (3x + 7)^2)^2 - y^2
it's in the form of a^2 - b^2 = (a+b)(a-b)
So ( (3x + 7)^2)^2 - y^2
= (3x+y+7)(3x-y+7)
let 9x^2 + 42x + 49 be 'x'
9x^2 + 42x + 49
(3x)^2 + 2×3x×7 + (7)^2
it's in the form of a^2 +2ab+ b^2 = (a+b)^2
so (3x)^2 + 2×3x×7 + (7)^2 = (3x + 7)^2
so 'x' = (3x + 7)^2
( (3x + 7)^2)^2 - y^2
it's in the form of a^2 - b^2 = (a+b)(a-b)
So ( (3x + 7)^2)^2 - y^2
= (3x+y+7)(3x-y+7)
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