x2(a-1)+a2xy+(a+1)y2
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The answer is given below :
Now,
(a - 1)x² + a²xy + (a + 1)y²
= (a - 1)x² + (a² - 1 + 1)xy + (a + 1)y²
= (a - 1)x² + {(a - 1)(a + 1) + 1}xy + (a + 1)y²
= (a - 1)x² + (a - 1)(a + 1)xy + xy + (a + 1)y²
= (a - 1)x{x + (a + 1)y} + y{x + (a + 1)y}
= (x + ay + y)(ax - x + y)
Thank you for your question.
Now,
(a - 1)x² + a²xy + (a + 1)y²
= (a - 1)x² + (a² - 1 + 1)xy + (a + 1)y²
= (a - 1)x² + {(a - 1)(a + 1) + 1}xy + (a + 1)y²
= (a - 1)x² + (a - 1)(a + 1)xy + xy + (a + 1)y²
= (a - 1)x{x + (a + 1)y} + y{x + (a + 1)y}
= (x + ay + y)(ax - x + y)
Thank you for your question.
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