Question

X2-b2 - a(2x-a)
Nature of the roots

Answer 1

Answer:

X² - b² - a(2x -a)

= x² -b² -2ax +a²

= x² - 2ax +a² -b²

D = b² - 4ac

D = (-2a)²- 4(1)(a²-b²)

D = 4a² -4a² +4b²

D = 4b² [i.e. a positive integer]

Here D >0 so

Roots are real and Distinct.

...........Hope this will help you...........

Answer 2

Answer:

X^2-b^2-a(2x-a)

X^2-b^2-2ax+a^2

X^2-2ax+a^2-b^2

D=b^2-4ac

D=(-2a)^2-4(1)(a^2-b^2)

D=4a^2-4a^2+4b^2

D=4b^2