Question

x²-(x+1)(x+2)/5x+1=6

Answer 1

$<b >Hey here is your Answer$

$= \frac{ {x}^{2} - [(x + 1)(x + 2)]}{5x + 1} = 6 \\ \\ = \frac{ {x}^{2} - [x(x + 2) + 1(x + 2)]}{5x + 1} = 6 \\ \\ = \frac{ {x}^{2} - [ {x }^{2} + 2x + x + 2]}{5x + 1} = 6 \\ \\ = \frac{ {x}^{2} - [ {x}^{2} + 3x + 2] }{5x + 1} = 6 \\ \\ = \frac{ {x}^{2} - {x}^{2} - 3x - 2}{5x + 1} = 6 \\ \\ = \frac{ - 3x - 2}{5x + 1} = 6 \\ \\ = - 3x - 2 = 6(5x + 1) \\ \\ = - 3x - 2 = 30x + 6 \\ \\ = - 2 - 6 = 30x + 3x \\ \\ = 33x = - 8 \\ \\ = x = \frac{( - 8)}{33} \: \: \: answer$

hope this helps you

### BE BRAINLY ###

Answer 2

$\dfrac{ {x}^{2} - (x + 1)(x + 2) }{5x + 1} = 6 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: .. \bold{(given}$

Solving the question in parts. First solving numerator which is [ x² - ( x + 1 )( x + 2 ) ].

x² - [ ( x + 1 )( x + 2 ) ]

x² - [ x( x + 2 ) + 1( x + 2 ) ]

x² - [ x²+ 2x + x + 2 ]

x² - x² - 3x - 2

- 3x - 2

Therefore, on simplifying the denominator we get - 3x - 2

Therefore, [ x - ( x + 1 )( x + 2 ) ] = - 3x - 2

Then,

$\dfrac{ {x}^{2} - (x + 1)(x + 2) }{5x + 1} = 6 \\ \\ \\ \frac{ - 3x - 2}{5x + 1} = 6 \\ \\ \\ - 3x - 2 = 6(5x + 1) \\ \\ - 3x - 2 = 30x + 6 \\ \\ - 8 = 33x \\ \\ - \dfrac{ 8}{33} = x$

Thus,

value of x satisfying the equation is - 8 / 33