Question

x2 +y2 = 68 and x-y=6 find x3 - y3

Answer 1

⭐⭐Hello friend...Ur answer is here⤵⤵

⚫ x^2+y^2=68 , x-y=6

➡(x-y)^2=x^2+y^2-2xy

➡6^2=68-2xy

➡36=68-2xy

➡2xy=32

➡xy=16

Now...

➡x^3-y^3=(x-y)(x^2+xy+y^2)

➡ x^3-y^3=6 (68+16)

➡ x^3+y^3=6×84

➡x^3-y^3=504

I HOPE IT IS HELPFUL TO YOU ☺

Answer 2

Heya !


Here is yr answer
______________________________



Given,

x² + y² = 68

x - y = 6

x³ - y³ = ?

Now,

x³ - y³ = (x-y) (x²+y²+xy)



x³ - y³ = (6) (68xy)

x³ - y³ = 408xy


Hope it hlpz....