Question

x³ + 3x² - 4x solve it ​

Answer 1

Step-by-step explanation:

${x}^{3} + 3 {x}^{2} - 4x \\ = {x}^{3} + 4 {x}^{2} - {x}^{2} - 4x \\ = {x}^{2} (x + 4) - x(x + 4) \\ = ( x + 4)( {x}^{2} - x) \\ = x(x + 4)(x - 1)$

Hope it helps you.

Answer 2

Step-by-step explanation:

Given:

${x}^{3} + 3 {x}^{2} - 4x$

To find: factors and zeros of polynomial

Solution:

Step 1: Take x common

$x( {x}^{2} + 3x - 4)$

Step 2: Split the middle term

$x( {x}^{2} + 4x - x - 4)$

Step 3: Take common from first two and last two terms

$x[x(x + 4) - 1(x + 4)]$

Step 4: Final factors are

$x( x + 4)(x - 1)$

Step 5: Find zeros by equating factors to zero

$x(x + 4)(x - 1) = 0 \\ \\ x = 0 \\ \\ or \\ \\ x = - 4 \\ \\ or \\ \\ x = 1$

Final answer:

Factors are x(x+4)(x-1)

Zeros are 0,-4 and 1.

Hope it helps you.

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