Math, asked by PhysicsisLove, 1 year ago

xsquare -3x-2 solve it

Answers

Answered by BlackVenom05
0
♦ x²- 3x - 2

[ here, the first thing is to find the militon factor of the middle term i.e. 3x by spliting ]

[ to find the militon factor of 3x take the first and the last digits ]

[ here, we donot count x² as digit so instead take 1 ]

[ first no. × second no. ]
1 × 2

[ now, in militon factor, the number which is formed i.e. 1 × 2, we need to take this number either by addition or by subtraction (according to the middle term) , here we will take (1+2) because (1+2) = 3 ]

♦ x² - 3x - 2

= x² - (1+2)x - 2

= x² - x - 2x - 2
[ after this we need to find the common out ]

= x(x-1) - 2(x+1)
[ here, x and -2 are common ]
[ here, we had done this because -2(x+1) = -2x-2 ]

= x(x+1) + 2(x-1)
[ we done this here because 2(x-1) = 2x-2 ]

= (x-1) (x+2)
[ take (x-1) as common, and x and 2 are left so take them as (x+2) ]

Answer is (x-1) (x+2)

hope \: it \: helps \: you

PhysicsisLove: = x² - x - 2x - 2
[ after this we need to find the common out ]
PhysicsisLove: I have not understood after this
BlackVenom05: I'm elaborating it...so that you can understand ......= x²-x-2x-2 = [( x×x-x) - x ] - [( 2×x)-2 ] here, in 1st one x is coming in both the no. so they are common. and the second no. 2 is common. so = x(x-1) -2(x+1)
BlackVenom05: as x(x-1)-2(x+1) = x²-x-2x-2
Answered by Anonymous
1

Step-by-step explanation:

♦ x²- 3x - 2

[ here, the first thing is to find the militon factor of the middle term i.e. 3x by spliting ]

[ to find the militon factor of 3x take the first and the last digits ]

[ here, we donot count x² as digit so instead take 1 ]

[ first no. × second no. ]

1 × 2

[ now, in militon factor, the number which is formed i.e. 1 × 2, we need to take this number either by addition or by subtraction (according to the middle term) , here we will take (1+2) because (1+2) = 3 ]

♦ x² - 3x - 2

= x² - (1+2)x - 2

= x² - x - 2x - 2

[ after this we need to find the common out ]

= x(x-1) - 2(x+1)

[ here, x and -2 are common ]

[ here, we had done this because -2(x+1) = -2x-2 ]

= x(x+1) + 2(x-1)

[ we done this here because 2(x-1) = 2x-2 ]

= (x-1) (x+2)

[ take (x-1) as common, and x and 2 are left so take them as (x+2) ]

Answer is (x-1) (x+2)

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