Math, asked by stylishchaitu8053, 1 year ago

∫xtan−1xdx= (a)(x2+12)tan−1x−x2(b)(x2+12)+tan−1x−x(c)(x2+1)tan−1x−x(d)(x2+1)tan−1x+x

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Answered by sprao534
1

Please see the attachment

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