Question

∆XYZ ~ ∆LMN . in ∆XYZ ,XY= 3 ,YZ=4 and in ∆ LMN , LN HYPOTENISE =10 Then find XZ AND LM​

Answer 1

in triangle XYZ,xy=3,yz=4, xz =?,to find hypotenuse xz? we put values in following formula.

$(xz) {?}^{2} = (xy) {?}^{2} + (yz) {?}^{2}$

=

$(xz) { }^{2} \: = 3 {}^{2} { + 4 }^{2}$

$(xz) {}^{2} = 9 + 16$

$(xz) {}^{2} = 25$

$xz = \sqrt{25 \: }$

$xz = 5$

In triangle LMN, ln=10,to find side lm=? we put values in following formula.

$ln = \frac{1}{2} \times lm$

$10 = \frac{1}{2} \times lm$

$lm = 5$