Question

y=0.5sin(314t-12.56x) find out amplitude, wave length, frequencyand maximum particle velocity

Answer 1

the equation is in the form of y=A sin(wt - kx)
therefore,
amplitude is 0.5

w=2πn
314=2πn
314/2×3.14=n
n=50
where 'n' is frequency

wavelength=1/n
=1/50
=0.02

max particle velocity=Aw
=0.5×314
=157.