Question

y+2x-19=0:2x-3y+3=0
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Answer 1

$\huge\underline\mathcal\red{Solution}$

The given pair of linear equations are :

☆ 2x + y - 19 = 0 .....(i)

☆ 2x - 3y + 3 = 0 ......(ii)

By using elimination method ...

• By subtracting both the eq . , we get ,

2x + y - 19 = 0

2x - 3y + 3 = 0

(-) (-) (-)

_____________

-4y - 22 = 0

-4y = 22

y = 22÷ 4

y = 11/2

By putting the value of y in eq.(i) ....we get ...

2x + y - 19 = 0

= 2x + 11/2 - 19 = 0

= 2x + (11 - 38)÷2 = 0

= 2x - 27/2 = 0

= 2x = 27/2

= x = 27/4

= x = 6.75