Math, asked by sudarshanbari, 7 months ago

(y+4)^2=x
find dy/
dx​

Answers

Answered by maneetdhillon
0

Step-by-step explanation:

(y+4)^2=x

x=2y+8 this is the best answer

Answered by Nachiketman
0

Answer: dy/dx = 1 / (2y + 8)

Step-by-step explanation:

(y+4)² = x

y² + 8y + 16 = x

Now differentiate wrt x -

2y dy/dx  + 8 dy/dx = 1

dy/dx  ( 2y + 8) = 1

dy/dx = 1 / (2y+8)

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