(y+4)^2=x
find dy/
dx
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0
Step-by-step explanation:
(y+4)^2=x
x=2y+8 this is the best answer
Answered by
0
Answer: dy/dx = 1 / (2y + 8)
Step-by-step explanation:
(y+4)² = x
y² + 8y + 16 = x
Now differentiate wrt x -
2y dy/dx + 8 dy/dx = 1
dy/dx ( 2y + 8) = 1
dy/dx = 1 / (2y+8)
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