Question

'y a screw gauge was found to be 0.026om. 0.028 cm, 0.029 cm.
O14. The diameter of a wire as measured by a screw gauge
0.027cm, 0.024 cm, and 0.027 cm. Calculate
(1) mean value of the diameter
(it) mean absolute error
(iii) relative error
(iv) percentage error.
Also express the result in terms of absolute error and percentage error.​

Answer 1

Explanation:

mean value of the diameter

1. (0.027+0.024+0.027)/3

0.026cm

mean error

0.027-0.026= 0.001

0.027-0.026=0.001

0.024-0.026=-0.002

2. mean absolute error

|0.001|+|0.001|+|0.002|

0.004

3. relative error

0.004/0.026

0.1538 which is approximately 0.154

4. percentage error

relative error * 100

0.154*100

15.4 percent