Question

y=√cos√sin√x , then find dy/dx

Answer 1

Step-by-step explanation:

we know d(√x)/DX = 1/(2√x) using this l

y=√cos√sin√x

dy/dx=d(√cos√sin√x)/d(cos√sin√x) × d(cos√sin√x)/d(√sin√x) × d(√sin√x)/d√x × d√x/dx

=1/(2√cos√sin√x) × (-sin√sin√x)×{1/(2√sin√x)} × 1/(2√x)

={-sin(√sin√x)}/{8√cos(√sin√x)×√sin(√x)×√x} answer