Question

y=e^x +e^-x
dy/dx=√y^2-4

Answer 1

Step-by-step explanation:

dy/dx= d/dx (e^x +e^-x)

= d/dx e^x + d/dx e^-x

=e^x +e^-x d/dx (-x) .......[ Using chain rule ]

=e^x + e^-x (-1)

=(e^x - e^-x)

= √ ( e^x + e^-x)^2 -4e^x x e^x

=√y^2 - 4...... [e^x + e^-x = y]