Y is convex set of x then order topology is same as subspace topology proof
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Topology is same as subspace topology proof
Topology is same as subspace topology proof
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Let X be an ordered set in the order topology, let Y be a subset of X that is convex in X. Then the order topology on Y is the same as the topology Y inherits as a subspace of X. ... Since the open rays of Y are a sub-basis for the order topology on Y , this topology is contained in the subspace topology.
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