Math, asked by Naiem4288, 6 months ago

Y=\sqrt{5+4x-x^{2}}[/what is the domain and range and what is this curve of the function]

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Answered by luisecubero77
2

Answer:

domain -1 <= x <= 5

interval [-1,5]

range 0 <= f(x) <= 3

interval [0,3]

Step-by-step explanation:

y = √5 + 4x - x²

x = - 2

√5 + 4(-2) - (-2)²

√5 - 8 - 4

√-7

no negative root

x = 6

√5 + 4(6) - (6)²

√5+ 24 - 36

√-7

no negative root

domain -1 <= x <= 5

interval [-1,5]

The value in y is 3, look the graph

range 0 <= f(x) <= 3

interval [0,3]

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