Y=\sqrt{5+4x-x^{2}}[/what is the domain and range and what is this curve of the function]
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Answer:
domain -1 <= x <= 5
interval [-1,5]
range 0 <= f(x) <= 3
interval [0,3]
Step-by-step explanation:
y = √5 + 4x - x²
x = - 2
√5 + 4(-2) - (-2)²
√5 - 8 - 4
√-7
no negative root
x = 6
√5 + 4(6) - (6)²
√5+ 24 - 36
√-7
no negative root
domain -1 <= x <= 5
interval [-1,5]
The value in y is 3, look the graph
range 0 <= f(x) <= 3
interval [0,3]
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