Question

y = x sin x² then value of dy/dx is​

Answer 1

Answer:

y=x sin(x^2)

dy/dx=x(cos(x^2)×2x) ×sin(x^2)

dy/dx=2x^2 cos(x^2) sin(x^2)

dy/dx=x^2 sin(2x^2)

Answer 2

Answer:

2x² * cos x²- sinx²

Explanation:

dy/dx = x*(cos x² *2x) - sin x². {dy/dx ( u*v )= u* v' - v* u'}

= 2x² * cos x²- sinx²