Question

y = -x2 + 6x -8, describe the roots.

Answer 1

Answer:

$-x^{2} +6x-8\\= -x^{2} +4x+2x-8\\=-x(x-4)+2(x-4)\\=(-x+2)(x-4)\\for  roots  (-x+2)(x-4)=0\\x=2or x=-4$

Step-by-step explanation:

Answer 2

Roots = 2 and -4

y = -x2 + 6x -8
= -x2 + 2x + 4x - 8
= -x(x - 2) + 4(x - 2)
= (x - 2) (-x + 4)
Therefore, x = 2 or x = -4