Question

y²- 3Y - 10 = 20 solve this factorisation

Answer 1

$\textbf{Answer :}$

[We make some corrections.]

Given that,

y² - 3y - 10 = 0

or, y² - (5 - 2)y - 10 = 0

or, y² - 5y + 2y - 10 = 0

or, y (y - 5) + 2 (y - 5) = 0

or, (y - 5) (y + 2) = 0

Either y - 5 = 0 or, y + 2 = 0

=> y = 5, y = - 2

Therefore, the required solution be

y = 5, - 2

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