y² +4y+3 Pls answer fast
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Answered by
1
y²+4y+3
y²+y+3y+3
y(y+1)+3(y+1)
y=-1,-3
Answered by
0
y² - 4y + 3
= y² - y - 3y + 3
= y ( y - 1 ) - 3 ( y - 1 )
= ( y - 3 )( y - 1 )
So,
y = 3 , y = 1
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