y2+7y-18 pls factorise asap
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We are given following mathematical expression for factorization
y² - 7y - 18
Since
y²×-18 = -18y²
So we have to write -7y into two parts in such a way that
product of them is equal to -18y² and addition of them is equal to -7y
Thus
We make following parts
-7y = - 9y + 2y
See
-9y×2y = -18y²
Hence
The expression becomes
y² - 7y - 18 = y² - 9y + 2y - 18
= y(y - 9) + 2(y - 9)
= (y - 9)(y + 2)
So
y² - 7y - 18 = (y - 9)(y + 2)
Thus factorization of y² - 7y - 18 is equal to (y - 9)(y + 2)
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