Math, asked by StarTbia, 1 year ago

y²=7y Compare the given quadratic equation to the general form and write values of a, b, c.

Answers

Answered by nikitasingh79
29

Quadratic equation : An equation of degree 2 is called a quadratic equation.


General form of Quadratic equation :


ay² + by+ c , where a,b,c are constants and a≠0.



SOLUTION:


GIVEN : Y²=7y


y² -7y = 0


On comparing with General form of Quadratic equation : ay² + by+ c = 0


Here, a= 1, b = -7 , c = 0.



Hence , the value of a= 1,b = -7 & c = 0



HOPE THIS WILL HELP YOU...


Answered by abhi178
47
we know, general form of quadratic equation is given ay² + by + c = 0 , coefficient of y² = a
coefficient of y = b , constant = c

here, given,
y² = 7y
y² - 7y + 0 = 0
compare with ay² + by + c = 0
a = 7 , b = -7 and c = 0

y² = 7y
=> y² - 7y = 0
=> y(y - 7) = 0
=> y = 0 and 7
hence, roots of y² - 7y are 0 and 7
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