y²=7y Compare the given quadratic equation to the general form and write values of a, b, c.
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Answered by
29
Quadratic equation : An equation of degree 2 is called a quadratic equation.
General form of Quadratic equation :
ay² + by+ c , where a,b,c are constants and a≠0.
SOLUTION:
GIVEN : Y²=7y
y² -7y = 0
On comparing with General form of Quadratic equation : ay² + by+ c = 0
Here, a= 1, b = -7 , c = 0.
Hence , the value of a= 1,b = -7 & c = 0
HOPE THIS WILL HELP YOU...
Answered by
47
we know, general form of quadratic equation is given ay² + by + c = 0 , coefficient of y² = a
coefficient of y = b , constant = c
here, given,
y² = 7y
y² - 7y + 0 = 0
compare with ay² + by + c = 0
a = 7 , b = -7 and c = 0
y² = 7y
=> y² - 7y = 0
=> y(y - 7) = 0
=> y = 0 and 7
hence, roots of y² - 7y are 0 and 7
coefficient of y = b , constant = c
here, given,
y² = 7y
y² - 7y + 0 = 0
compare with ay² + by + c = 0
a = 7 , b = -7 and c = 0
y² = 7y
=> y² - 7y = 0
=> y(y - 7) = 0
=> y = 0 and 7
hence, roots of y² - 7y are 0 and 7
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