y2+y-6=0.pleaszzzzzzzzzzzz
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Answered by
12
Hey!!!
That's easy
=> y² + y - 6 = 0
=> y² + 3y - 2y - 6 = 0
=> y(y + 3) -2(y + 3) = 0
=> (y - 2)(y + 3) = 0
=> y = 2 or y = -3
Hope this helps
That's easy
=> y² + y - 6 = 0
=> y² + 3y - 2y - 6 = 0
=> y(y + 3) -2(y + 3) = 0
=> (y - 2)(y + 3) = 0
=> y = 2 or y = -3
Hope this helps
13deep:
hlw
Answered by
5
y^2 + y-6 =0
y^2 +3y - 2y -6=0
y ( y + 3 ) - 2( y+3 ) = 0
(y-2)(y+3) =0
y= 2
y=-3
y^2 +3y - 2y -6=0
y ( y + 3 ) - 2( y+3 ) = 0
(y-2)(y+3) =0
y= 2
y=-3
yed
yes
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