Question

यदि cot Q = 12/5 तो sinQ का क्या मान होगा ?​

Answer 1

Answer:

cot Q = 12/5

cot Q = adjacent side/opposite side

adjacent side/opposite side = 12/5

by using Pythagoras theorem:-

$(hy) {}^{2} = (base) {}^{2} + (height) {}^{2} \\ (hy) {}^{2} = (12) {}^{2} + (5) {}^{2} \\ (hy) {}^{2} = 144 \: + 25 \\ (hy) {}^{2} = 169 \\ hy = \sqrt{169 } \\ hy = 13$

sinQ = opposite side/hypotenuse

sinQ = 5/13.......ANSWER

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