Question

Ycube+ysquare minus y minus 1

Answer 1

y³ + y² - y -1

= y²(y + 1) - 1(y + 1)

=( y² - 1)( y +1)

=(y -1)(y + 1)( y +1)
hence, (y -1) , (y +1) and (y +1) are the three factors of y³ +y² - y -1

hence,
roots :-
(y -1)(y+1)² = 0
y = 1 , -1

hence, 1 , -1 and -1 are the roots of given polynomial .

Answer 2

HI there !

y³ + y² - y -1 

Taking common terms outside :-

y²(y + 1) - 1(y + 1) 

( y² - 1) ( y +1)         
 (y -1)(y + 1)( y +1)               -----> factorized form 

(y -1) , (y +1) and (y +1) are the  factors .

y - 1 = 0
y = 1

y + 1 = 0
y = -1

Zeroes = 1 , - 1 , -1