Yes got 40 marks in a test getting 3 marks for each right answer and losing 1 mark for each wrong answer had 4 marks been awarded for each correct answer in 2 must be deducted for each in correct answer then you should have scored 50 marks how many questions are there in the test
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Answered by
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Let correct question = x
And incorrect question = y
Yash scored 40 marks in a test, getting 3marks for each right answer and losing1 mark for each wrong answer.
3x - y = 40
Subtract 3x both sides we get
-Y = 40 – 3x
Change the sign we get
Y = 3x – 40 …(1)
Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then Yash would have scored 50 marks
We get
4x – 2y = 50
Plug the value of y we get
4x – 2(3x - 40) =50
4x – 6x + 80 = 50
-2x = - 30
X = 15
Plug this value back in equation first we get
Y = 3x – 40
Y = 3* 15- 40
Y = 45 – 40
Y = 5
So total question are x + y = 15 + 5 = 20
And incorrect question = y
Yash scored 40 marks in a test, getting 3marks for each right answer and losing1 mark for each wrong answer.
3x - y = 40
Subtract 3x both sides we get
-Y = 40 – 3x
Change the sign we get
Y = 3x – 40 …(1)
Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then Yash would have scored 50 marks
We get
4x – 2y = 50
Plug the value of y we get
4x – 2(3x - 40) =50
4x – 6x + 80 = 50
-2x = - 30
X = 15
Plug this value back in equation first we get
Y = 3x – 40
Y = 3* 15- 40
Y = 45 – 40
Y = 5
So total question are x + y = 15 + 5 = 20
Answered by
0
Answer:
Let x be the number of right answers and y be the number of wrong answers.
∴ According to the question ,
3x−y=40⟶(i)
and , 2x−y=25⟶(ii)
On substraction : x=15
putting the value of x in ⟶(i)
3(15)−y=40
y=5
∴ Number of right answers=15 answers
Number of wrong answers=5 answers.
Total Number of questions 5+15=20
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